School Project Β· Mathematics & Probability

The Monty Hall Problem

Should you switch doors β€” or does it not matter? The answer will surprise you.

Three doors. One car. Two goats. The host opens a door β€” and now asks: do you switch? Most people say it doesn't matter. They are wrong.

The Setup

Picture the following scenario: you are at the final stage of a game show. In front of you stand three doors, labelled A, B, and C from left to right. Behind one door lies the prize you have been competing for β€” a brand-new car, for example. The other two doors hold goats. Pick the wrong door, and you get nothing.

The game show host requests that you choose a door. Let us say the chosen door is B. Then the host β€” who knows what is behind each door β€” goes over and opens door C. Revealed behind it is a goat. Now, the host asks you: would you like to switch your choice to door A?

If you stay
β…“
chance of winning
33.3% β€” Lose
If you switch
β…”
chance of winning
66.6% β€” Win

At this point, most assume the probability of winning to be 50%. It is natural to do so, since we appear to be considering only two options β€” A and B. However, the solution to the Monty Hall Problem says that there is a significantly higher probability of winning if you switch.

Switching doubles your chances of winning β€” from 1 in 3 to 2 in 3.

If You Stay With Door B

Let us consider the case where you picked door B and refused to switch. There are three equally likely scenarios for where the car could be:

Staying with your choice No switch

1.
If the car was behind A, the host would open C, and you would lose.
2.
If the car was behind C, the host would open A, and you would lose in this scenario as well.
3.
If the car was behind B β€” your original pick β€” you would win.

Result: staying gives you a 1 in 3 chance of winning β€” a 66.6% chance of losing.

If You Switch to Door A

Now, say you chose B and decided to switch every time the host offers you the chance:

Switching your choice Always switch

1.
If the car was behind A, the host opens C, you switch to A and win the car.
2.
If the car was behind C, the host opens A, you switch to C and win.
3.
If the car was behind B β€” your original pick β€” you lose.

Result: switching gives you a 2 in 3 chance of winning β€” from 33.3% all the way up to 66.6%.

The key insight is this: when you first picked door B, you had a 1/3 chance of being right. That means the other two doors together held a 2/3 chance of concealing the car. When the host eliminates one of those doors by showing a goat, the entire 2/3 probability concentrates on the remaining door β€” door A. Switching is therefore always the rational choice.

Child deciding whether to switch or stay after one door is opened in the Monty Hall probability problem game show
Should the contestant switch doors or stay? Switching gives a better chance to win.

A Brief History of the Problem

The Monty Hall Problem originated from a 1975 letter written by Steve Selvin to The American Statistician, titled "A Problem in Probability." It was named after Monty Hall, the charismatic host of the American television game show Let's Make a Deal, whose three-door format inspired the scenario.

The problem rose to widespread fame in 1990, when Marilyn vos Savant β€” holder of the Guinness World Record for highest recorded IQ at the time β€” described and solved it in her "Ask Marilyn" column in Parade magazine. Her correct answer (switch!) triggered an avalanche of outraged letters from readers, including mathematics professors, who insisted she was wrong. She was right.

Shaurya Ghanty
Standard XI Β· School Project Essay
La Martiniere for Boys, Kolkata